5x+4/6x^2-x

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Solution for 5x+4/6x^2-x equation:


x in (-oo:+oo)

(4/6)*x^2+5*x-x = 0

2/3*x^2+4*x = 0

DELTA = 4^2-(0*2/3*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-4)/(2/3*2) or x = (-16^(1/2)-4)/(2/3*2)

x = 0 or x = -6

x in { -6, 0 }

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